Congruences for q[p/8](modp)q^{[p/8]}\pmod p II

preprint2014arXivOpen access

Abstract

Let Z\Bbb Z be the set of integers, and let pp be a prime of the form 4k+14k+1. Suppose q∈Zq\in\Bbb Z, 2∤q2\nmid q, p∤qp\nmid q, p=c2+d2p=c^2+d^2, c,d∈Zc,d\in\Bbb Z and c≡1(mod4)c\equiv 1\pmod 4. In this paper we continue to discuss congruences for q[p/8](modp)q^{[p/8]}\pmod p and present new reciprocity laws, but we assume 4p=x2+qy24p=x^2+qy^2 or p=x2+2qy2p=x^2+2qy^2, where [⋅][\cdot] is the greatest integer function and x,y∈Zx,y\in\Bbb Z.

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