Computing the Ramsey Number R(K5−P3,K5)R(K_5-P_3,K_5)

preprint2012arXivOpen access

Abstract

We give a computer-assisted proof of the fact that R(K5−P3,K5)=25R(K_5-P_3, K_5)=25. This solves one of the three remaining open cases in Hendry's table, which listed the Ramsey numbers for pairs of graphs on 5 vertices. We find that there exist no (K5−P3,K5)(K_5-P_3,K_5)-good graphs containing a K4K_4 on 23 or 24 vertices, where a graph FF is (G,H)(G,H)-good if FF does not contain GG and the complement of FF does not contain HH. The unique (K5−P3,K5)(K_5-P_3,K_5)-good graph containing a K4K_4 on 22 vertices is presented.

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