Characterizations of all-derivable points in B(H)B(H)

preprint2014arXivOpen access

Abstract

Let K{\mathcal{K}} and H{\mathcal{H}} be two Hilbert space, and let B(K,H)B({\mathcal{K}},{\mathcal{H}}) be the algebra of all bounded linear operators from K{\mathcal{K}} into H{\mathcal{H}}. We say that an element G∈B(H,H)G\in B({\mathcal{H}},{\mathcal{H}}) is an all-derivable point in B(H,H)B({\mathcal{H}},{\mathcal{H}}) if every derivable linear mapping φφ at GG (i.e. φ(ST)=φ(S)T+Sφ(T)φ(ST)=φ(S)T+Sφ(T) for any S,T∈B(H)S,T\in B(H) with ST=GST=G) is a derivation. Let both φ:B(H,K)→B(H,K)φ: B({\mathcal{H}},{\mathcal{K}})\rightarrow B({\mathcal{H}},{\mathcal{K}}) and ψ:B(K,H)→B(K,H)ψ: B({\mathcal{K}},{\mathcal{H}})\rightarrow B({\mathcal{K}},{\mathcal{H}}) be two linear mappings. In this paper, the following results will be proved : if Yφ(W)=ψ(Y)WYφ(W)=ψ(Y)W for any Y∈B(K,H)Y\in B({\mathcal{K}},{\mathcal{H}}) and W∈B(H,K)W\in B({\mathcal{H}},{\mathcal{K}}), then φ(W)=DWφ(W)=DW and ψ(Y)=YDψ(Y)=YD for some D∈B(K)D\in B({\mathcal{K}}). As an important application, we will show that an operator GG is an all-derivable point in B(H,H)B({\mathcal{H}},{\mathcal{H}}) if and only if G≠0G\neq 0.

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