Abstract

We prove that if A⊆{1,2,…,N}A\subseteq \{ 1,2,\dots, N \} does not contain any solution to the equation x1+⋯+xk=y1+⋯+ykx_1+\dots+x_k=y_1+\dots+y_k with distinct x1,…,xk,y1,…,yk∈Ax_1,\dots,x_k,y_1,\dots,y_k\in A, then ∣A∣≪k3/2N1/k.|A|\ll {k^{3/2}}N^{1/k}.

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