An upper bound for the number of independent sets in regular graphs

Write ${\cal I}(G)$ for the set of independent sets of a graph $G$ and $i(G)$ for $|{\cal I}(G)|$. It has been conjectured (by Alon and Kahn) that for an $N$-vertex, $d$-regular graph $G$, $i(G) \leq \left(2^{d+1}-1\right)^{N/2d}.$ If true, this bound would be tight, being achieved by the disjoint union of $N/2d$ copies of $K_{d,d}$. Kahn established the bound for bipartite $G$, and later gave an argument that established $i(G)\leq 2^{\frac{N}{2}\left(1+\frac{2}{d}\right)}$ for $G$ not necessarily bipartite. In this note, we improve this to $i(G)\leq 2^{\frac{N}{2}\left(1+\frac{1+o(1)}{d}\right)}$ where $o(1) \rightarrow 0$ as $d \rightarrow \infty$, which matches the conjectured upper bound in the first two terms of the exponent. We obtain this bound as a corollary of a new upper bound on the independent set polynomial $P(λ,G)=\sum_{I \in {\cal I}(G)} λ^{|I|}$ of an $N$-vertex, $d$-regular graph $G$, namely $$ P(\gl,G) \leq (1+\gl)^{\frac{N}{2}} 2^{\frac{N(1+o(1))}{2d}} $$ valid for all $\gl > 0$. This also allows us to improve the bounds obtained recently by Carroll, Galvin and Tetali on the number of independent sets of a fixed size in a regular graph.

No reviews yet.

No comments yet.