A Note on Property Testing of the Binary Rank

preprint2023arXivOpen access

Abstract

Let MM be a n×mn\times m (0,1)(0,1)-matrix. We define the ss-binary rank, brs(M)br_s(M), of MM to be the minimal integer dd such that there are dd monochromatic rectangles that cover all the 11-entries in the matrix, and each 11-entry is covered by at most ss rectangles. When s=1s=1, this is the binary rank,~br(M)br(M), known from the literature. Let R(M)R(M) and C(M)C(M) be the set of rows and columns of~MM, respectively. We use the result of Sgall (Comb. 1999) to prove that if MM has ss-binary rank at most~dd, then ∣R(M)∣⋅∣C(M)∣≤(d≤s)2d|R(M)|\cdot |C(M)|\le {d\choose \le s}2^{d} where (d≤s)=∑i=0s(di){d\choose \le s}=\sum_{i=0}^s{d\choose i}. This bound is tight; that is, there exists a matrix M′M' of ss-binary rank dd such that ∣R(M′)∣⋅∣C(M′)∣=(d≤s)2d|R(M')|\cdot |C(M')|= {d\choose \le s}2^{d}. Using this result, we give a new one-sided adaptive and non-adaptive testers for (0,1)(0,1)-matrices of ss-binary rank at most dd (and exactly dd) that makes O~((d≤s)2d/ε)\tilde O\left({d\choose \le s}2^d/ε\right) and O~((d≤s)2d/ε2)\tilde O\left({d\choose \le s}2^d/ε^2\right) queries, respectively. For a fixed ss, this improves the query complexity of the tester of Parnas et al. (Theory Comput. Syst. 2021) by a factor of Θ~(2d)\tilde Θ(2^d).

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