Abstract
We prove the following theorem. Suppose that is a trim DFA on the Boolean alphabet . The language is well-ordered by the lexicographic order $\slex$ iff whenever the non sink states are in the same strong component, then is a sink. It is easy to see that this property is sufficient. In order to show the necessity, we analyze the behavior of a $\slex$-descending sequence of words. This property is used to obtain a polynomial time algorithm to determine, given a DFA , whether is well-ordered by the lexicographic order. Last, we apply an argument in \cite{BE,BEa} to give a proof that the least nonregular ordinal is .
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