Abstract
The 2-LCPS problem, first introduced by Chowdhury et al. [Fundam. Inform., 129(4):329-340, 2014], asks one to compute (the length of) a longest palindromic common subsequence between two given strings and . We show that the 2-LCPS problem is at least as hard as the well-studied longest common subsequence problem for four strings (the 4-LCS problem). Then, we present a new algorithm which solves the 2-LCPS problem in time, where denotes the length of and , denotes the number of matching positions between and , and denotes the number of distinct characters occurring in both and . Our new algorithm is faster than Chowdhury et al.'s sparse algorithm when .
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