Abstract

As a natural extension of the Four Color Theorem, Hajós conjectured that graphs containing no K5K_5-subdivision are 4-colorable. Any possible counterexample to this conjecture with minimum number of vertices is called a {\it Hajós graph}. Previous results show that Hajós graphs are 4-connected but not 5-connected. A kk-separation in a graph GG is a pair (G1,G2)(G_1,G_2) of edge-disjoint subgraphs of GG such that ∣V(G1∩G2)∣=k|V(G_1\cap G_2)|=k, G=G1∪G2G=G_1\cup G_2, and Gi⊈G3−iG_i\not\subseteq G_{3-i} for i=1,2i=1,2. In this paper, we show that Hajós graphs do not admit a 4-separation (G1,G2)(G_1,G_2) such that ∣V(G1)∣≥6|V(G_1)|\ge 6 and G1G_1 can be drawn in the plane with no edge crossings and all vertices in V(G1∩G2)V(G_1\cap G_2) incident with a common face. This is a step in our attempt to reduce Hajós' conjecture to the Four Color Theorem.

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